No se puede obtener un objeto JSON en respuesta a una solicitud Ajax con wp_ajax

Question

No se puede obtener un objeto JSON en respuesta a una solicitud Ajax con wp_ajax

4

266600 2014-11-17

Tengo unproblema con WordPress y Ajax.

Estaesmi parte de JavaScript (la recorté unpoco):

 var posts = $.ajax({
    type: 'POST',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action: 'myAjaxFunc' },
    done: function(response) {
        return response;
    }
}).responseText;

$.each(posts, function() {
    $('#someSelect').append( $('<option</option>').text(this.name).val(this.id) );
});

Mi código PHPesel siguiente:

 function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }

    header("Content-type: application/json");
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

El script obtiene la respuesta Ajax de admin-ajax. Desafortunadamente,la consola arroja unerror cuando llega a lainstrucción eachen el código JavaScript ... dice:

 "Uncaught TypeError: Cannot use 'in' operator to search for '4' in Array".

Si hago un console.log demis "publicaciones" var obtengo una cadena 'Array'. Noimporta cómopase la variable $listen PHP,siempre devolverá una cadena. La consulta devuelvepublicacionesen otros lugares,por lo quenoestá vacía. Intenté sin json_encode,con y sin declararelencabezado,usando wp_send_json(),poniendo ob_clean() antes de hacereco de lamatriz,colocando lamatrizen unamatriz ... Pero siempreentraen ajax como una cadena Array y eachnopuede recorrerla.

Esto debería ser algomuy simple ynopuedoentenderpor quénofunciona. Notengo otroserrores o advertencias de JavaScript o PHP ytodo lo demásfuncionabien.

I have a problem with WordPress and Ajax.

This is my JavaScript part (I trimmed it a bit):

var posts = $.ajax({
    type: 'POST',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action: 'myAjaxFunc' },
    done: function(response) {
        return response;
    }
}).responseText;

$.each(posts, function() {
    $('#someSelect').append( $('<option</option>').text(this.name).val(this.id) );
});

My PHP code is as follows:

function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }

    header("Content-type: application/json");
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

The script gets the Ajax response from admin-ajax. Unfortunately the console throws an error when it gets to the each statement in the JavaScript code... it says:

"Uncaught TypeError: Cannot use 'in' operator to search for '4' in Array".

If I do a console.log of my "posts" var I get a string 'Array'. No matter how I pass the $list variable in PHP it will always return a string. The query returns posts elsewhere, so it's not empty. I tried without json_encode, with and without declaring header, using wp_send_json(), putting ob_clean() before echoing the array, putting the array into an array... But it always gets into ajax as a string Array and each cannot cycle through it.

This should be a very simple thing and I can't understand why it's not working. I don't have other JavaScript or PHP errors or warnings and everything else runs fine.

- ¿Qué ves cuando vas a http://www.example.com/wp-admin/admin-ajax.php?action=myAjaxFunc
  
  What do you see when you go to http://www.example.com/wp-admin/admin-ajax.php?action=myAjaxFunc
  - 0
  - 2014-11-17
  - czerspalace
- ¿Algúnprogresoen tupregunta?¿Podría hacer un seguimiento?
  
  Any progress on your question? Could you please follow up?
  - 0
  - 2015-04-15
  - kaiser
- oh ...estoes de hace 5meses ... Respondí ami propiapreguntapor cierto,al día siguiente lapubliqué,usandopartes de la respuesta BODA82 - simplementeno lamarqué como la respuesta correcta;@toscho agregó su seguimientomuchomástarde ayer.Nopuedo verificar si su respuestatambiénesbuena ahora,aunquetiene sentido.
  
  oh... this is from 5 months ago... I did answer to my own question by the way the next day I posted it, using bits of BODA82 answer - I just didn't marked it as the correct answer; @toscho added his follow up much later yesterday I can't verify if his answer is also good now, it makes sense though
  - 0
  - 2015-04-16
  - unfulvio

3 respuestas

votos

2

2014-11-17

Casi ahí con sufunción PHP. Noesnecesario configurarelencabezado. (Editar:también,asumiendo que get_posts()en realidad devuelve resultados).

 function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

Y su Javascript:

 $.ajax({
    url: "<?php bloginfo('url'); ?>/wp-admin/admin-ajax.php",
    type: "POST",
    data: "action=myAjaxFunc",
    success: function(results) {
        var posts = JSON.parse(results);
        console.log(results);
        $.each(posts, function() {
            $('#someSelect').append( $('<option></option>').text(this.name).val(this.id) );
        });
    },
    error: function() {
        console.log('Cannot retrieve data.');
    }
});

Almost there with your PHP function. No need to set the header. (Edit: Also, assuming get_posts() is actually returning results.)

function myAjaxFunc() {

    $posts = get_posts( array(
        'posts_per_page'   => -1,
        'orderby'          => 'title',
        'order'            => 'ASC',
        'post_type'        => 'my-post-type',
        'post_status'      => array( 'publish', 'draft' )
    ) );

    $list = array();
    foreach ( $posts as $post ) {
        $list[] = array(
            'id'   => $post->ID,
            'name' => $post->post_title,
            'link' => get_permalink( $post->ID ),
        );
    }
    echo json_encode( $list );
    die;
}
add_action( 'wp_ajax_nopriv_myAjaxFunc', 'myAjaxFunc' );
add_action( 'wp_ajax_myAjaxFunc', 'myAjaxFunc' );

And your Javascript:

$.ajax({
    url: "<?php bloginfo('url'); ?>/wp-admin/admin-ajax.php",
    type: "POST",
    data: "action=myAjaxFunc",
    success: function(results) {
        var posts = JSON.parse(results);
        console.log(results);
        $.each(posts, function() {
            $('#someSelect').append( $('<option></option>').text(this.name).val(this.id) );
        });
    },
    error: function() {
        console.log('Cannot retrieve data.');
    }
});

Cuandoguarda algunos datos usando JSON.stringify () y luegonecesita leerlosen php.El siguiente códigofuncionóparamí.json_decode (html_entity_decode (stripslashes ($jsonString)));

When you save some data using JSON.stringify() and then need to read that in php. The following code worked for me. json_decode( html_entity_decode( stripslashes ($jsonString ) ) );
- 0
- 2019-12-04
- Vishal Tanna

2

2015-04-15

Hay una salida.Utilice completeen lugar de success o done:

 posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    complete: function(results) {

Eintente eliminar async:false sielproblemapersiste.

There is a way out. Use complete instead of success or done:

posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    complete: function(results) {

And try to remove async:false if the problem persists.

unfulvio · Accepted Answer · 2014-11-18

8

2014-11-18

La respuesta de BODA82 ayudó,perofinalmenteme di cuenta de que debería haber reemplazadoelmétodo responseText conelmétodo responseJSONen mi código JavaScript. Enel siguienteejemplo,estaba almacenando los resultados de la respuesta Ajaxen una variable. No sabía que había unmétodoespecíficopara obtener la respuestaen JSON. Deestamanera,el objeto/matriz con get_posts() resultados se devuelve correctamente yno como una cadena:

 posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    done: function(results) {
        // Uhm, maybe I don't even need this?
        JSON.parse(results);
        return results;
    },
    fail: function( jqXHR, textStatus, errorThrown ) {
        console.log( 'Could not get posts, server response: ' + textStatus + ': ' + errorThrown );
    }
   }).responseJSON; // <-- this instead of .responseText

Notapara unomismo,perotambién un consejogeneral: sinopuede arreglar algopor lanoche,es una señal de que debeirse a la cama,leer un libro y contarestrellas. Seencontrará una respuesta a lamañana siguiente,cuanto antes,mejor: D

BODA82's answer helped, but eventually I realized that I should have replaced responseText with responseJSON method in my JavaScript code. In the example below I was storing the Ajax response results in a variable. I didn't know there was a specific method to get the response in JSON. In a such way the object/array with get_posts() results is returned correctly and not as a string:

posts = $.ajax({
    type: 'GET',
    url: ajaxurl,
    async: false,
    dataType: 'json',
    data: { action : 'getHotelsList' },
    done: function(results) {
        // Uhm, maybe I don't even need this?
        JSON.parse(results);
        return results;
    },
    fail: function( jqXHR, textStatus, errorThrown ) {
        console.log( 'Could not get posts, server response: ' + textStatus + ': ' + errorThrown );
    }
   }).responseJSON; // <-- this instead of .responseText

Note to self, but also general advice: if you can't fix something in the evening it's a sign you should go to bed, read a book, and count stars. An answer will be found the next morning, the earlier the better :D